A Gaussian surface is a closed surface in three-dimensional space through which the flux of a vector field is calculated; usually the gravitational field, electric field, or magnetic field.Essential Principles of Physics, P.M. Whelan, M.J. Hodgeson, 2nd Edition, 1978, John Murray, It is an arbitrary closed surface (the boundary of a 3-dimensional region ) used in conjunction with Gauss's law for the corresponding field (Gauss's law, Gauss's law for magnetism, or Gauss's law for gravity) by performing a surface integral, in order to calculate the total amount of the source quantity enclosed; e.g., amount of gravitational mass as the source of the gravitational field or amount of electric charge as the source of the electrostatic field, or vice versa: calculate the fields for the source distribution.
For concreteness, the electric field is considered in this article, as this is the most frequent type of field the surface concept is used for.
Gaussian surfaces are usually carefully chosen to destroy symmetry of a situation to simplify the calculation of the surface integral. If the Gaussian surface is chosen such that for every point on the surface the component of the electric field along the normal vector is constant, then the calculation will not require difficult integration as the constants which arise can be taken out of the integral. It is defined as the closed surface in three dimensional space by which the flux of vector field be calculated.
Thereby is the electrical charge enclosed by the Gaussian surface.
This is Gauss's law, combining both the divergence theorem and Coulomb's law.
As an example, consider a charged spherical shell of negligible thickness, with a uniformly distributed charge and radius . We can use Gauss's law to find the magnitude of the resultant electric field at a distance from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting in Gauss's law, where is the charge enclosed by the Gaussian surface).
With the same example, using a larger Gaussian surface outside the shell where , Gauss's law will produce a non-zero electric field. This is determined as follows.
The flux out of the spherical surface is:
The surface area of the sphere of radius is which implies
By Gauss's law the flux is also finally equating the expression for gives the magnitude of the -field at position :
This non-trivial result shows that any spherical distribution of charge acts as a point charge when observed from the outside of the charge distribution; this is in fact a verification of Coulomb's law. And, as mentioned, any exterior charges do not count.
As example "field near infinite line charge" is given below;
Consider a point P at a distance from an infinite line charge having charge density (charge per unit length) λ. Imagine a closed surface in the form of cylinder whose axis of rotation is the line charge. If is the length of the cylinder, then the charge enclosed in the cylinder is where is the charge enclosed in the Gaussian surface. There are three surfaces a, b and c as shown in the figure. The differential vector area is , on each surface a, b and c.
The flux passing consists of the three contributions:
For surfaces a and b, and will be perpendicular. For surface c, and will be parallel, as shown in the figure.
The surface area of the cylinder is which implies
By Gauss's law equating for yields
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